Question

solve the product of x spuare (xcube-4x+3)

Answer 1

here is your answer
$p (x) = {x}^{2} ( {x}^{3} - 4x + 3) \\ p(x) = {x}^{5} - 4 {x}^{3} + 3 {x}^{2} \\ putting \: x = 1 \\ {1}^{5} - 4( {1)}^{3} + 3( {1)}^{2} \\ 1 - 4 + 3 = 0 \\ it \: means \: that \:( x - 1) \: is \: a \\ \: factor \: of \: p(x) \: (because \ \\ (x - 1) = 0 \: so \: x \: = 1) \\ \\ divide \: p(x) \: by \: (x - 1) \\ p(x) = {x}^{5} - 4{x}^{3} + 3 {x}^{2} = \\ (x - 1) ({x}^{4} + {x}^{3} - 3 {x}^{2} ) \\ (x - 1) \times {x}^{2} ( {x}^{2} +x - 3) \\ {x}^{2} (x - 1)( {x}^{2} + x - 3)$
hope this helps you
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