solve the qno 20 fast
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SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT
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Answer:
→3^x-8=3^(2-x)
→3^x-8=9/3^x
let 3^x be a
→a-8=9/a
→a²-8a-9=0
→a²-9a+a-9=0
→a(a-9)+1(a-9)=0
a =-1 and 9
but 3^x≠-1 since it should be positive
→3^x=9
→3^x=3²
x=2
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