Question

Solve the quadrate equation by factorization
4 (-3 2)^2 - (2x - 3)-14 = 0​

Answer 1

Step-by-step explanation:

4(2x – 3)2 – (2x – 3) – 14 = 0

Let 2x – 3 = y

Then 4y2 – y – 14 = 0

⟹ 4y2 – 8y + 7y – 14 = 0 ⟹

4y(y – 2) + 7 ( y – 2) = 0 ⟹

(y – 2) (4y + 7) = 0

Answer 2

Step-by-step explanation:

4(2x – 3)2 – (2x – 3) – 14 = 0

Let 2x – 3 = y

Then 4y2 – y – 14 = 0

⟹ 4y2 – 8y + 7y – 14 = 0

⟹ 4y(y – 2) + 7 ( y – 2) = 0

⟹ (y – 2) (4y + 7) = 0

if y-2=0. or. 4y+7=0

y=2. or. y=-7/4

2x-3=2. or. 2x-3=-7/4

2x=5. or. 2x=5/4

x= 5/2. or. x= 5/8