Question

solve the quadratic eqn and give two roots
${x}^{2} + 3x - 4$
​

Answer 1

Answer:

$x = 1 \: and \: - 4$✔✔

Step-by-step explanation:

${x}^{2} + 3x - 4 \\ we \: use \: middle \: term \: spliting \: to \: solve \: this \: eqn \\ {x}^{2} + 4x - x - 4 \\ x(x + 4) - 1(x + 4) \\ x - 1 = 0 \\ x = 1 \\ x + 4 = 0 \\ x = - 4$

Answer 2

SOLUTION

=) x^2 +3x-4=0

=) x^2 +4x-x -4=0

=) x(x+4) -1(x+4)=0

=) (x+4) (x-1)=0

=) x+4= 0 or x-1=0

=) x= -4 or x= 1

hope it helps ✔️