Math, asked by wwwankit4431, 1 year ago

Solve the quadratic equation 12abx^2-(9a^2-8b^2)x-6ab=0 by quadratic formula

Answers

Answered by niksauckland
96

Answer:

I have attached the answer

Attachments:
Answered by saif64963
0

Answer:

x = 3a/4b , -2b/3a

Step-by-step explanation:

Given:

12abx^2-(9a^2-8b^2)x-6ab=0

Our quadratic equation formula is given below:

x = -b±(\sqrt{b^{2} -4ac}) / 2a

for a standard quadratic equation ax^2+bx+c=0

On comparing

a = 12ab

b= -(9a^2-8b^2)

c= -6ab

On substituting this we get

x = [(9a^2-8b^2)±(81a^4+64b^4-144a^2b^2 +288a^2b^2)^0.5 ]/24ab

  =  [(9a^2-8b^2)±(9a^2+8b^2)]/24ab

x = 3a/4b , -2b/3a

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