Question

solve the quadratic equation​

Answer 1

Answer:

$x=\frac{\sqrt3}{4}, \ x=-\frac{2}{\sqrt3}$

Step-by-step explanation:

$4\sqrt3x^2+5x-2\sqrt3=0\\ factorising \ (3\sqrt3\times2\sqrt3)=24 \ in \ such \ a \ way \ that \ sum \ of \ factors \ is \ 5,\\\therefore \ 4\sqrt3x^2+8x-3x-2\sqrt3=0\\\therefore \ 4x(\sqrt3x+2)-\sqrt3(\sqrt3x+2)=0\\\therefore \ (4x-\sqrt3)(\sqrt3x+2)=0\\\therefore \ x=\frac{\sqrt3}{4} \ and \ x=-\frac{2}{\sqrt3}$