Math, asked by dpa8, 11 months ago

solve the quadratic equation 2x^2+ax-a^2=0​

Answers

Answered by rosangiri53
3

2x^2+2ax-ax-a^2=0

2x(x+a)-a(x+a)= 0

(2x-a)(x+a)= 0

so

x=a/2,-a


dpa8: tq
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