Question

solve the quadratic equation (2x+3)(x-4)=6

$pls \: solve \: this \: equation$

Answer 1

(2x^2 - 8x +3x -12)= 6

2x^2 -5x -12 -6 = 0

2x^2 - 5x -18= 0

2x^2 +4x -9x -18= 0

2x( x+2) -9( x+2)= 0

( 2x -9)( x+2)= 0

x= 9/2, -2

Answer 2

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