Question

Solve the quadratic equation : √2x^ + x+√2 =0​

Answer 1

Step-by-step explanation:

$\bf\ { \sqrt{2} x}^{2} + x - \sqrt{2} = 0 \\ \\ \tt\ \implies { \sqrt{2} x}^{2} + 2x - x - \sqrt{2} = 0 \\ \\ \sf\ \implies \: \sqrt{2}x( x + \sqrt{2}) - 1(x + \sqrt{2} ) = 0 \\ \\\tt\ \implies ( \sqrt{2}x - 1)(x + \sqrt{2} ) = 0$

Answer 2

Answer:

Here is your answer

Step-by-step explanation:

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