Question

Solve the quadratic equation 2x² +ax -a² = 0 for x

Answer 1

Answer:

we know, $\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

so for,

$a=2,\:b=a,\:c=-a^2:\quad x=\frac{-a\pm \sqrt{a^2-4\cdot \:2\left(-a^2\right)}}{2\cdot \:2}$

$if,x= \frac{-a-\sqrt{a^2-4\cdot \:2\left(-a^2\right)}}{2\cdot \:2}\\ then,\\ x = -a$

$if, x = \frac{-a+\sqrt{a^2-4\cdot \:2\left(-a^2\right)}}{2\cdot \:2}\\then,\\x=a/2$

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