Question

Solve the quadratic equation 2x²+x+1 =0
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Answer 1

Answer:

x≠R (-1+√-7/ 4)

Step-by-step explanation:

1) Solve the quadratic equation:

  2x²+bx+c =0 using x= -b+√b²-4ac/ 2a

  x= -1 + √1² - 4x2x1/2x2

2) x= -1 + √1² - 4x2x1/2x2

   any expression multiplied by 1 remains the same

   x= -1+√1²-4x2/ 2x2

   x= -1+√1²-4x2/ 2x2

   1 raised to any power equals 1

   x= -1+√1-4x2/ 2x2

   x= -1+√1²-4x2x1/ 2x2

   multiply the number (4x2=8)

   x= -1+√1-8/ 2x2

   x= -1+√1²-4x2x1/ 2x2

   multiply the number (2x2)

   x= -1+√1-8/ 4

3) x= -1+√1-8/ 4

    calculate the difference

    x= -1+√-7/ 4

4) x= -1+√-7/ 4

   the square root of a negitave number does not exist in the set or real

   numbers

   x≠R

5) x≠R (-1+√-7/ 4)