Question

Solve the Quadratic Equation:3x²-4√3x-5=0​

Answer 1

Answer:

formula=-b+-√b²-4ac/2a

-(-4√3)+-√-4√3²+4(3)(-5)

+4√3+-√16×3-60

4√3+-4√3-60

=4√3-4√3-60 or 4√3+4√3-60

Answer 2

Step-by-step explanation:

$3 {x}^{2} - 4 \sqrt{3} x - 5 = 0$

$3 {x}^{2} - 5 \sqrt{3} x + \sqrt{3} x - 5 = 0$

$(3 {x}^{2} + \sqrt{3} x) + ( - 5\sqrt{3} x - 5) = 0$

$\sqrt{3} x( \sqrt{3} x + 1) - 5( \sqrt{3} x + 1) = 0$

$( \sqrt{3} x + 1)( \sqrt{3} x - 5)$

$\sqrt{3} x + 1 = 0$

$\sqrt{3}x = - 1$

$x = \frac{ - 1}{ \sqrt{3} }$

$\alpha = \frac{ - \sqrt{3} }{3}$

$\sqrt{3} x - 5 = 0$

$\sqrt{3}x = 5$

$x = \frac{5}{ \sqrt{3} }$

$\beta = \frac{5 \sqrt{3} }{3}$