Question

solve the quadratic equation√3x²+ 4x-7√3=0 by factorisation method​

Answer 1

Answer:

Answers=>

x=-7/√3

x=√3

Step-by-step explanation:

√3x²+ 4x-7√3=0

√3x²-3x+7x-7√3=0

√3x(x-√3)+7(x-√3)=0

(√3x+7)(x-√3)=0

(√3x+7)=0 or (x-√3)=0

x=-7/√3 or x=√3

Hope this helps you.

Answer 2

Given data: The quadratic equation $\sqrt{3} x^{2} +4x-7\sqrt{3}=0$

To Find: The required solution for the given equation $\sqrt{3}x^{2} +4x-7\sqrt{3} =0$ by factorization method.

Solution:

• Factorization can be done by grouping the terms and taking the common factors out.
• $\sqrt{3}x^{2} +4x-7\sqrt{3} =0$
• Split the middle term,
• $\sqrt{3}x^{2} -3x+7x- 7\sqrt{3}=0$
• Group the terms together,
• $(\sqrt{3}x^{2} -3x)+(7x-7\sqrt{3})=0$
• Take the common factors out,
• $\sqrt{3}x(x-\sqrt{3})+7(x-\sqrt{3})=0$ , since $\sqrt{3}$×$\sqrt{3}=3$
• $(x-\sqrt{3})+(\sqrt{3}x+7)=0$
• By using zero order property it can be written as,
• $x-\sqrt{3}=0$ $or$ $\sqrt{3}x+7=0$
• $x=\sqrt{3}$ or $\sqrt{3}x=-7\\x=\frac{-7}{\sqrt{3} }$
• Therefore, the required solution of the equation $\sqrt{3}x^{2} +4x- 7\sqrt{3}=0$ by factorization method is $x=\sqrt{3} , x=\frac{-7}{\sqrt{3} }$