Question

Solve the quadratic equation : 3y² + 7y + 1 = 0 by formula.​

Answer 1

Answer:

Comparing With Standard Form

ax2 + bx + c = 0

a = 3, b = 7 , c =1

Step-by-step explanation:

b2-4ac = (7)² - 4×3×1

= 49 - 12

= 37

x = –b + √b²- 4ac

2a

-7 + √37 = -7 - √37

2×3. 2×3

= 7 - 37. =7+37

6. 6

= 30. = 44

6. 6

x = 5. = 44

6