Question

Solve the quadratic equation -4x^2+2x-5=0

Answer 1

Step-by-step explanation:

-4x^2+2x-5=0

4x^2-2x+5=0

So,

D=b^2-4ac

(-2)^2-4×4×5

4-80

-76

So, D<0

Roots are imaginary