solve the quadratic equation:
4x^2 - 4ax + ( a^2 - b^2) = 0
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4x^2-4ax+(a^2-b^2)=0
=> (4x^2-4ax+a^2)-b^2=0
=>(2x-a)^2-b^2=0
=>{2x-a-b}{2x-a+b}=0
=> x=(a+b)/2 , (a-b)/2
=> (4x^2-4ax+a^2)-b^2=0
=>(2x-a)^2-b^2=0
=>{2x-a-b}{2x-a+b}=0
=> x=(a+b)/2 , (a-b)/2
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hope it may help u .......
. name Harshit
. name Harshit
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