Question

solve the quadratic equation 4x quadratic equation 4 root 3 X square + 5 x -
$4 \sqrt{3} {x}^{2} + 5x - 2 \sqrt{3 = 0}$

Answer 1

Answer:

The value of x is -2√3/3   and √3/4

Step-by-step explanation:

Given ::- 4√3x² +5x -2√3 = 0

Solution ::-

By factorisation method ::-

4√3 x (-2√3) = -24        8 x (-3) = 24

And,  8 - 3 = 5 (middle term)

4√3 x² -3x + 8x -2√3 = 0

√3x (4x-√3)  + 2 (4x -√3) = 0

(√3x + 2 ) (4x - √3) = 0

√3x + 2 = 0

x = -2/√3

Rationalising -

x = -2√3 / 3

4x - √3 = 0

x = √3/4

Therefore the value of x is  -2√3 /3   and √3/4

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