Question

solve the quadratic equation 4x2+4bx-(a2-b2)=0

Answer 1

4x² +4bx -(a² -b²) = 0

4x² +4bx -a² + b² =0

(2x)² + 2.(2x).b + b² -a² =0

(2x + b)² -a² = 0

use formula,

a²-b² = (a -b)(a + b)

{2x + b -a}{2x + b +a} =0

x = (a - b)/2 , - (a + b)/2

Answer 2

4x²+4bx-(a²-b²)
4x²+4bx-a²+b²
applying quadratic formula

-b+-√b²-4ac/2a

-4b+-√(-4b)² + 4×4(a²-b²)/8

-4b+-√16b²+16a²- 16b²/8

-4b +- √ 16a²/8

-4b +- 4a /8

-b +- a /2

-(a+b) /2 , a-b /2

Hope it helps!!!