Math, asked by tishyameshram2526, 13 days ago

Solve the quadratic equation√5 x^2-7x+√20=0​

Answers

Answered by tennetiraj86
2

Step-by-step explanation:

Given:-

The quadratic equation√5 x^2-7x+√20=0

To find:-

Solve the quadratic equation√5 x^2-7x+√20=0

Solution:-

Given quardratic equation is

√5 x^2-7x+√20=0

=> √5x^2 -5x -2x +√20 = 0

=> √5x^2-5x-2x+2√5 = 0

=>√5x(x-√5) -2(x-√5) = 0

=> (x-√5) (√5x-2) = 0

=> x-√5 = 0 or √5x -2 = 0

=> x =√5 or √5 x = 2

=>x =√5 or x = 2/√5

The roots are √5 and 2/√5

Answer:-

The roots of the given quardratic equation are √5 and 2/√5

Used Method:-

Splitting the middle term

Answered by ayushbhattacharya9
0

Step-by-step explanation:

six hundred twenty five into two hundred seventy nine into sixteen find the product

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