Math, asked by tishyameshram2526, 7 hours ago

Solve the quadratic equation√5 x^2-7x+√20=0
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Answers

Answered by atharvsc7
0

Answer:

this is your answer bro or sis .!!

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Answered by paridhimalhotra07
1

\sqrt{5}x^{2} - 7x + \sqrt{20} =0\\\sqrt{5}x^{2} -7x +2\sqrt{5}=0\\\sqrt{5}x^{2}  -5x-2x+2\sqrt{5}=0\\\sqrt{5}x(x-\sqrt{5})-2(x-\sqrt{5})=0\\(x-\sqrt{5})(\sqrt{5}x-2)=0\\\\x=\sqrt{5}  , \frac{2}{\sqrt{5} }

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