Question

solve the quadratic equation 5m^2+2m+1=0​

Answer 1

Answer:

5m^2+2m+1=0

Here a=5,b=2,c=1

By quadratic formula,

D=b^2-4ac= 2^2-4x5x1= 4-20=-16

As D is less than 0,

the equation does not have real roots.

(OR IF THIS EQUATION DOES HAVE REAL ROOTS ACCORDING TO THE SOLUTION OF YOUR BOOK, THEN PLEASE CHECK THE SIGNS CAREFULLY)

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Answer 2

Here a = coefficient of m^2 = 5

b = coefficient of m = 2

c = constant term = 1

D = discriminant = b ^2 - 4ac

= 2^2 - 4 × 5 × 1

= 4 - 20 = - 16

root ( D ) = root ( -16 ) = root ( ( -1 ) × 16 ))

= root ( -1 ) × root ( 16 ) = i × 4 = 4i

since root ( - 1 ) = i ( imaginary number )

using quadratic formula :

m = ( - b + - root ( D ) ) / 2a

= ( -2 + - 4i ) / 2 ×5 = ( -2 + - 4i ) / 10

= 2 ( -1 + - 2i ) / 10 = ( -1 + - 2i ) / 5

m = 1/5 × ( -1 + - 2i )