Question

solve the quadratic equation 6x^2-31x+40=0​

Answer 1

Step-by-step explanation:

here is answer.. i hope u understand this

Answer 2

$6{x}^{2} - 31x + 40 = 0 \\ x = \frac{ - b \sqrt[ + - ]{ {b}^{2} - 4ac} }{2a} \\ \: \: \: = \frac{31 \sqrt[ + - ]{ {31}^{2} - 4 \times 6 \times 40} }{2 \times 6} \\ \: \: \: = \frac{31 \sqrt[ + - ]{961 - 960}}{12} \\ \: \: \: = \frac{31 (+ - )1}{12} \\ \\ so \: \: \: \: \alpha = \frac{31 + 1}{12} \\ \: \: \: \: \: \: \: \: \: \: \: \: = \frac{32}{12} \\ \: \: \: \: \: \: \: \: \: \: \: \: = \frac{8}{3} \\ \\ and \: \: \: \: \beta = \frac{31 - 1}{12} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{30}{12} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{15}{6}$