Question

Solve the quadratic equation 7x^2+x+30

Answer 1

Given:

7x²+x+30 = 0 (let, as 'x' is a root)

On comparing with the general form of a quadratic polynomial, i.e., ax²+bx+c=0

We get, a=7, b=1, and, c=30

★Solution★

On applying the Quadratic formula for finding the value of 'x':

$x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a}$

Therefore,

$x = \frac{ - 1± \sqrt{ {(1)}^{2} - 4(7)(30)} }{2(7)}$

$x = \frac{ - 1± \sqrt{1 - 840} }{14}$

$x = \frac{ - 1 + \sqrt{ - 839} }{14} \: \: or \: \: \frac{ - 1 - \sqrt{ - 839} }{14}$

Therefore, the solution of the quadratic equation are not real,

i.e., x ∉ R

Answer 2

Answer:

$\huge\underline{ \underline{ \red {your \: \: \: answer}}}$

Step-by-step explanation:

$\bf\blue{ \underline{ \mapsto: using \: splitting \: method}}\\ \\ \bf\pink{ \implies: {7x}^{2} + x - 30 = 0 } \\ \\ \bf\green{ \implies: {7x}^{2} + (15x - 14x) - 30 = 0 } \\ \\ \bf\purple{ \implies: {7x}^{2} + 15x - 14x - 30 = 0 } \\ \\ \bf\orange{ \implies:x(7x + 15) - 2(7x + 15) = 0} \\ \\ \bf\red{ \implies:(x - 2)(7x + 15) = 0 } \\ \\ \bf\red{ \implies: (x - 2) = 0} \\ \\ \bf\red{ \implies: x = 2} \\ \\ \bf\red{ \implies: (7x + 15 )= 0} \\ \\ \bf\red{ \implies:x = \frac{ - 15}{7} }$

$\large\boxed{ \fcolorbox{red}{lime}{hope \: it \: help \: you}}$