Question

Solve the quadratic equation 8x^2-14x+3=0​

Answer 1

Answer:

$8x {}^{2} - 14x + 3 = 0 \\ 8x {}^{2} - (12x + 2x) + 3 = 0 \\ 8x {}^{2} - 12x - 2x + 3 = 0 \\ 4x(2x - 3) - 1(2x - 3) = 0 \\ (2x - 3)(4x - 1) = 0 \\ x = \frac{3}{2} and \: \: \frac{1}{4}$

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Answer 2

Answer:

$8 {x}^{2} - 14x + 3 = 0 \\ 8 {x}^{2} - 12x - 2x + 3 = 0 \\ 4x(2x - 3) - 1(2x - 3) = 0\\ (4x - 1 )(2x - 3) = 0 \\ if \: 4 x - 1 = 0 \\ x = \frac{1}{4 } \\ if \: 2x - 3 = 0 \\ x = \frac{3}{2}$

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