Question

Solve the quadratic equation 8x^2+2^x-3=0

Answer 1

Answer:

x=_3/2and x= 1/4 this is the answer

8x^2+2x_3=0

8x^2+12x_2x_3=0

4x(2x+3)_1(2x+3)=0

(4x_1)(2x+3)=0

4x-1=0, 2x+3=0

x=1/4 ,. x=-3/2

Answer 2

Answer:

8x^2+2x-3

8x^2+(6-4)x-3

8x^2+6x-4x-3

2x(4x+3)-1(4x+3)

(2x-1)(4x+3)