Question

Solve the quadratic equation 9x^2-3x-20=0 by completing the square method.
answer step by step asap please.

Answer 1

Answer:

9x²-3x-20=0

dividing the whole equation by 9, we get

x²-3x/9-20/9=0

x²-x/3-20/9=0

(x-1/6)²-(1/6)²-20/9=0

(x-1/6)²-(1/36)-20/9=0

(x-1/6)²-1/36-20/9=0

(x-1/6)²-(1+80)/36=0[ LCM of 36&9 is 4]

(x-1/6)²-81/36=0

(x-1/6)²=81/36

x-1/6=+√81/36

x-1/6=+9/6

when 9/6 is positive then

x-1/6=9/6

x=9/6+1/6

x=10/6

when 9/6 is negative then

x-1/6=-9/6

x=-9/6+1/6

x=-8/6

x=-4/3

so, x=10/6 & x=-4/3

hope it will help you.

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Answer 2

Answer:

Here, is the answer of your question

Explanation: