solve the quadratic equation a) 2x^-3x-5=0
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Answered by
1
Step-by-step explanation:
2x² - 3x- 5 = 0
2x² + 2x - 5x - 5 = 0
2x(x + 1) -5(x+1) = 0
(x + 1)(2x - 5) = 0
x = -1 , x = 5/2
Answered by
0
Answer:
given equation is ...
2x^2-3x-5=0.
2x^2-5x+2x-5=0.
2x(X-1)+5(X-1)=0
(x-1)(2x +5)=0.
then .. x=1, -5/2
I hopes its helps u.
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