Math, asked by kaleshwarravidas4, 7 months ago

solve the quadratic equation a) 2x^-3x-5=0​

Answers

Answered by sam885104
1

Step-by-step explanation:

2x² - 3x- 5 = 0

2x² + 2x - 5x - 5 = 0

2x(x + 1) -5(x+1) = 0

(x + 1)(2x - 5) = 0

x = -1 , x = 5/2

Answered by pc0354525
0

Answer:

given equation is ...

2x^2-3x-5=0.

2x^2-5x+2x-5=0.

2x(X-1)+5(X-1)=0

(x-1)(2x +5)=0.

then .. x=1, -5/2

I hopes its helps u.

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