Question

solve
the quadratic equation: (a + b)²x2 + 8(a? – b2 ) x + 16(a - b)2 = 0​

Answer 1

Answer:

Step-by-step explanation:

x = - b -+ √b2-4ac ÷ 2a

x = -8(a2-b2) -+ √64(a2-b2)^2 - 64(a-b)^2 (a+b)^2 ÷ 2(a+b)^2

x = -8(a2-b2) -+ √64 [(a2-b2)^2 - (a-b)^2 (a+b)^2 ÷ 2(a+b)^2

x = -8(a2-b2) -+ 8 [(a2-b2) - (a-b)(a+b)] ÷ 2(a+b)^2

x = -8(a2-b2) -+ 8 [(a2-b2) - (a2-b2)] ÷ 2(a+b)^2

x = -8(a2-b2) ÷ 2(a+b)^2

x = -8(a+b)(a-b) ÷ 2(a+b)^2

x = -8(a-b) ÷ 2(a+b)

x = -4(a-b)/(a+b)

Hope it helped...

Please mark it as 'Brainliest'