solve the quadratic equation by factorisation method
0.02t²-0.04t=0.03
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0.02t²-0.04t=0.03
0.01 (2t²-4t) = 0.01 (3)
cancel 0.01 on both sides
It can be written as 2t² - 4t = 3
t = 1+0.5 √10 and 1-0.5√10
0.01 (2t²-4t) = 0.01 (3)
cancel 0.01 on both sides
It can be written as 2t² - 4t = 3
t = 1+0.5 √10 and 1-0.5√10
Anonymous:
see it now
could you simplify the answer
i did it
still not getting ur point
ohh, got it
just try to understand
thank you
no body can give a better explanation than this
i siad i got the answer. "Thank You"
i got that
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