Question

Solve the quadratic equation by factorisation method.​

Answer 1

Answer:

$7 x - 3x$

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Answer 2

Answer ⤵️

$\sqrt{3} {x}^{2} + 4x - 7 \sqrt{3} = 0 \\ = 7 \sqrt{3} \times \sqrt{3} = 7 \times 3 = 21 \\ = \sqrt{3} {x}^{2} + (7x - 3x) - 7 \sqrt{3} = 0 \\ = \sqrt{3} {x}^{2} + 7x - 3x - 7 \sqrt{3} = 0 \\ = x( \sqrt{3} x + 7) - \sqrt{3} ( \sqrt{3} x + 7) = 0 \\ we \: know \: that \: \: \sqrt{3} \times \sqrt{3} = 3 \\ = ( \sqrt{3} x + 7)(x - \sqrt{3} ) = 0 \\ = \sqrt{3} x + 7 = 0 \\ \sqrt{3} x = - 7 \\ x = \frac{ - 7}{ \sqrt{3} } \\ x - \sqrt{3} = 0 \\ x = \sqrt{3} \\ \\ so \: x = \frac{ - 7}{ \sqrt{3} } or \: x = \sqrt{3}$

Explanation:

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