Question

solve the quadratic equation by factorisation method (2x+3)²=25​

Answer 1

Step-by-step explanation:

Here's what you were searching for

Answer 2

$\huge\underbrace{Answer}$

FORMULA TO KNOW:-

( a + b )² = a² + b² + 2ab

Now lets do Problem using this identity

(2x + 3)² = 25

(2x)² + (3)² + 2(2x)(3) = 25

4x² + 9 + 12x = 25

4x² + 12x + 9 -25 = 0 (Transpose 25 to RHS)

4x² + 12x - 16 = 0

Now solve the quadratic eqaution by splitting middle term

4x² + 16x - 4x -16 =0

4x(x + 4) -4(x + 4) =0

(x + 4) ( 4x -4) =0

x + 4 =0

x = - 4

4x - 4 =0

4x = 4

x = 1

So,Required values of -4 , 1

VERIFICATION

by substuiting values of x should equal to LHS=RHS

CASE -1 At x= -4

(2x + 3)² = 25

(2(-4) + 3 )² = 25

( -8 + 3)² = 25

(-5)² = 25

25 = 25

Case 1 verified

CASE -2

(2x + 3)² = 25

(2(1) + 3)² =25

(5)² = 25

25 = 25 Hence both cases verified

FINAL ANSWER SO VALUE OF X IS -4,1