Math, asked by ldheletedaccount23ll, 2 months ago

solve the quadratic equation by factorisation method √3x+11x+6√3=0​
\begin{gathered} \\ \end{gathered}

write an appropriate and explained answer, please don't give irrelevant answers.
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Answers

Answered by Anonymous
17

\rm 3x+11x+6√3=0

\begin{gathered}\begin{gathered}\rm \sqrt{3} x^{2} + 9x + 2x + 6 \sqrt{3} = 0 \\ \end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\rm \sqrt{3x} (x + 3 \sqrt{3} ) + 2(x + 3 \sqrt{3} ) = 0 \\ \end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\rm (x + 3 \sqrt{3} )( \sqrt{3} x + 2) = 0 \\ \end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\rm x + 3 \sqrt{3} = 0 \\ \end{gathered}\end{gathered}

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OR

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\rm \sqrt{3x} + 2 = 0

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Hope, this will help you, don't spam or please don't report. and this is only the correct answer :)

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