Question

solve the quadratic equation by factorisation method 6y²-y-15=0​

Answer 1

6y²-y-15

6y²+9y-10y-15

3y(2y+3) -5 (2y+3)

(2y+3)(3y-5)

Answer 2

☯GIVEN :

• $\bf {6y^2 - y - 15=0}$

☯TO FIND :

• The zeros of the quadratic equation.

➲SOLUTION :

$\implies \sf{6y^2 - y - 15= 0}$

• By factorisation method :

$\implies \sf{6y^2 - 10y + 9y - 15 = 0}$

$\implies \sf{2y \bigg(3y - 5 \bigg) + 3 \bigg(3y - 5\bigg) = 0}$

$\implies \sf{\bigg(3y - 5\bigg) \bigg(2y + 3 \bigg) = 0}$

$\implies \sf{\bigg(3y - 5\bigg) = 0 \: , \: \bigg(2y + 3\bigg) = 0}$

$\implies\sf{3y = 0 + 5 \: , \: 2y = 0 - 3}$

$\implies\sf{3y = 5 \: , \: 2y= - 3}$

$\implies{\underline {\boxed{\purple{\bf{y = \dfrac{5}{3} \: , \: y = \dfrac{ - 3}{2}}}}}}$

$\huge{ \pink{ \therefore}}$ The zeros of the quadratic equation are $\bf{\dfrac{ 5}{3}}$ and $\bf{\dfrac{ - 3}{2}}$.