Solve the quadratic equation by factorisation method
x²-3√3x+6=0
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Answer:
x²-3√3x+6 = 0
=> x²-√3x-2√3x+6 = 0
=> x(x-√3) -2√3(x-√3) = 0
=> (x-√3) (x-2√3) = 0
=> (x-√3) = 0 and (x-2√3) = 0
=> x = √3 and 2√3
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