Question

Solve the quadratic equation by factorization. 2x2

– 11x + 14 = 0​

Answer 1

Answer:

factoring  2x2-11x+14

The first term is,  2x2  its coefficient is  2 .

The middle term is,  -11x  its coefficient is  -11 .

The last term, "the constant", is  +14

Step-1 : Multiply the coefficient of the first term by the constant   2 • 14 = 28

Step-2 : Find two factors of  28  whose sum equals the coefficient of the middle term, which is   -11 .

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Use the form ax2+bx+cax2+bx+c, to find the values of aa, bb, and cc.

a=2,b=−11,c=14a=2,b=-11,c=14

Consider the vertex form of a parabola.

a(x+d)2+ea(x+d)2+e

Substitute the values of aa and bb into the formula d=b2ad=b2a.

d=−112(2)d=-112(2)

Multiply 22 by 22.

d=−114d=-114

Find the value of ee using the formula e=c−b24ae=c-b24a.

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e=−98e=-98

Substitute the values of aa, dd, and ee into the vertex form a(x+d)2+ea(x+d)2+e.

a(x+d)2+ea(x+d)2+e.

2(x - 11/4)² - 9/8