Question

solve the quadratic equation by factorization method m^2-14m+13=0

Answer 1

$\: \: \: \: \: \: \: \: {m}^{2} - 14m + 13 = 0 \\ = > {m}^{2} - 13m - m + 13 = 0 \\ = > m(m - 13) - 1(m - 13) = 0 \\ = > (m - 13)(m - 1) = 0 \\ = > m = (1)and \: also(13).$






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Answer 2

Answer:

13 and 1 are the zeroes of the given quadratic equation.

Step-by-step explanation:

Explanation:

Given that, $m^2 - 14m + 13 = 0$

• The polynomial equations of degree two in one variable of type f(x) = ax2 + bx + c = 0 and with a, b, c∈R and a ≠0 are known as quadratic equations.

• It is a quadratic equation in its general form, where "a" stands for the leading coefficient and "c" for the absolute term of f(x).

Step 1:

We have, $m^2 - 14m + 13 = 0$

⇒ $m^2 - 13m -m + 13 = 0$

⇒ m(m - 13) - 1(m - 13) = 0

⇒ (m - 13) (m -1) = 0

⇒ m - 13 = 0 and m -1 = 0

⇒m = 13 and m = 1

Final answer:

Hence, 13 and 1 are the zeroes of the given quadratic equation.

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