Question

solve the quadratic equation by factorization method.
${x}^{2} - 3 \sqrt{3 }x + 6 = 0$
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Answer 1

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$x {}^{2} - 3 \sqrt{3x + 6 = 0}$

$x {}^{2} - 2 \sqrt{3x + \sqrt{3x + 6 = 0} }$

$x(x - 2 \sqrt{3) - \sqrt{3( x - 2 \sqrt{3) = 0} } }$

$(x - \sqrt{3)(x - 2 \sqrt{3) = 0} }$

x = √3, 2√3