Question

Solve the quadratic equation by
formula method
2a^+5a+2=0​

Answer 1

Step-by-step explanation:

2a² + 5a + 2 = 0

compare it with...

Ax² + Bx + C = 0

so, A = 2 , B = 5 , C = 2

$a( \alpha ,\beta ) = \frac{-B \: ± \sqrt{B {}^{2} - 4AC}}{2A} \\ \\ a( \alpha ,\beta ) = \frac{ - 5 \: ± \: \sqrt{(5 ){}^{2} - 4 \times 2 \times 2} }{2 \times 2} \\ \\ a( \alpha ,\beta ) = \frac{ - 5 \: ± \: \sqrt{25 - 16} }{4} \\ \\ a( \alpha ,\beta ) = \frac{ - 5 \: ± \: \sqrt{9} }{4} \\ \\a( \alpha ,\beta ) = \frac{ - 5 \: ± 3}{4} \\ \\ a( \alpha ) = \frac{ - 5 + 3}{4} = - \frac{ 2}{4} = - \frac{ 1}{2} \\ \\ a( \beta ) = \frac{ - 5 - 3}{4} = - \frac{ 8}{4} = - \frac{2}{1} \\ \\ roots \: of \: a \: = - \frac{ 1}{2} \: and \: - 2$