Question

solve the quadratic equation by quadratic formula: 2(x/x+1)^2-5(x/x+1)+2=0​

Answer 1

The given quadratic equation is 2x

2

+5x+2=0

On comparing with ax

2

+bx+c=0

We get, a=2,b=5,c=2

∴ b

2

−4ac=(5)

2

−4×2×2

=25−16

=9

x=

2a

−b±

b

2

−4ac

=

2×2

−5±

9

=

4

−5±3

x=

4

−5+3

x=−

2

1

or x=−2

∴ −

2

1

and −2 are the roots of given quadratic equation.

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