Question

solve the quadratic equation by the
$6x ^{2} + x - 2 = 0$
method of completing the perfect square : 1)6x^2+x- 2=0
​

Answer 1

Answer:

${6x}^{2} + x - 2 = 0$

${6x}^{2} + (4 - 3)x - 2 = 0$

${6x}^{2} + 4x - 3x - 2 = 0$

$2x(3x + 2) - 1(3x + 2) = 0$

$(3x + 2)(2x - 1) = 0$

$(3x + 2) = 0 \: and \: (2x - 1) = 0$

$3x = - 2 \: and \: 2x = 1$

x = -2/3 and x = 1/2

Ans. -2/3, 1/2

Hope it helps.

Answer 2

$\small\red{\boxed{Question = 6 {x}^{2} + x - 2 = 0}.} \\ \\ \small\orange{\underline{\underline{solution}} : - } \\ \\ \color{purple}6 {x}^{2} + x - 2 = 0 \\ \\ \color{purple}6 {x}^{2} +( 4 - 3)x - 2 = 0 \\ \\ \color{purple}6 {x}^{2} + 4x - 3x - 2 = 0 \\ \\ \color{purple} 2x(3x + 2) - 1(3x + 2) = 0 \\ \\ \color{purple}(2x - 1)(3x + 2) = 0 \\ \\ \color{purple}2x - 1 = 0 \: \: , \: \: 3x + 2 = 0 \\ \\ \color{purple}2x = 1 \: \: , \: \: 3x = - 2 \\ \\ \color{purple}x = \frac{1}{2} \: \: , \: \: x = \frac{ - 2}{3} \\ \\ \small\green{\boxed{x = \frac{1}{2} and \frac{ -2 }{3} \: \: is \: the \: answer }} \\ \\ \small\pink{\boxed{\boxed{it's ᭄亗 乄 ＭꫝղᎥនh 乄 亗✯❤࿐}}}$

Answer 3

$\small\red{\boxed{Question = 6 {x}^{2} + x - 2 = 0}.} \\ \\ \small\orange{\underline{\underline{solution}} : - } \\ \\ \color{purple}6 {x}^{2} + x - 2 = 0 \\ \\ \color{purple}6 {x}^{2} +( 4 - 3)x - 2 = 0 \\ \\ \color{purple}6 {x}^{2} + 4x - 3x - 2 = 0 \\ \\ \color{purple} 2x(3x + 2) - 1(3x + 2) = 0 \\ \\ \color{purple}(2x - 1)(3x + 2) = 0 \\ \\ \color{purple}2x - 1 = 0 \: \: , \: \: 3x + 2 = 0 \\ \\ \color{purple}2x = 1 \: \: , \: \: 3x = - 2 \\ \\ \color{purple}x = \frac{1}{2} \: \: , \: \: x = \frac{ - 2}{3} \\ \\ \small\green{\boxed{x = \frac{1}{2} and \frac{ -2 }{3} \: \: is \: the \: answer }} \\ \\ \small\pink{\boxed{\boxed{it's ᭄亗 乄 ＭꫝղᎥនh 乄 亗✯❤࿐}}}$