Question

Solve the quadratic equation by using quadratic formula: y^2
+ 4y + 3 = 0
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Answer 1

This is the answer in attachment. Hope it helps you and you mark it as Brainlist.

Answer 2

Answer:

-1 , -3

Step-by-step explanation:

y²+ 4y + 3 = 0

a=1, b=4, c=3

y= $\frac{-4+\sqrt{16-12}}{2}$  or, $\frac{-4-\sqrt{16-12}}{2}$

 = $\frac{-2}{2}$ or, $\frac{-6}{2}$

= -1 or -3