Question

Solve the quadratic equation by using quadratic formula: y^2
+ 4y + 3 = 0
​

Answer 1

view the above pic u will get ur answer ,i.e.,

y = -1, -3

Answer 2

${y}^{2} \: + \: 4y + \: 3 = 0$

$a = 1 \: \: b= 4 \: c = 3$

$by \: using \: quadratic \: formula$

$d = {b}^{2} \: - 4ac$

${4}^{2} - 4 \times 1 \times 3$

$16 - 12$

$d = 4$

$x = \frac{ - b + - \sqrt{d} }{2a}$

$\frac{ - 4 + - \sqrt{4} }{2}$

$\frac{ - 4 + - 2}{2}$

$\frac{ - 4 + - 2}{2}$

$x = - 1 \: and \: - 3$

hope this will help you and marks it as brainlist plzzzzzzzzz