Question

solve the quadratic equation of the roots exits 4√3x+5x-2√3=0​

Answer 1

$4 \sqrt{3} {x}^{2} + 5x - 2 \sqrt{3 } = 0 \\ = > 4 \sqrt{3} {x}^{2} + 8x - 3x - 2 \sqrt{3} = 0 \\ = > 4x( \sqrt{3} x + 2) - \sqrt{3} ( \sqrt{3} x + 2) = 0 \\ = > (4x - \sqrt{3} )( \sqrt{3} x + 2) = 0 \\ \\ \\ so \: .x = \frac{ \sqrt{3} }{4} or \: - \frac{2}{ \sqrt{3} }$

May be my answer is true..

when I try to answer of your question,in that time I found some mistake in your question that is you missed "x²"