solve the quadratic equation t^2+3t-10=0
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Solutions of Quadratic equation t²+3t-10=0 are (-5, 2)
GIVEN:
t²+3t-10=0
TO FIND:
Solve the given quadratic equation
SOLUTION:
We will solve the given quadratic equation by factorizing
Given t²+3t-10=0
Split the term 3t as 5t - 2t [ ∵ 5 × 2 =10 ]
⇒ t² + 5t - 2t -10
Take t and 2 common as shown below
⇒ t (t+5) - 2(t +5)
Now take (t+5) common
⇒ (t+5) (t - 2)
⇒ t+5 = 0 and t - 2 = 0
t = -5 t = 2
Therefore solutions of Quadratic equation t²+3t-10=0 are (-5, 2)
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