Question

solve the quadratic equation.
$2 {y}^{2} + 2y - 3 = 0$
please it's urgent.​

Answer 1

Answer:

y=-1 and y=3

Step-by-step explanation:

${y }^ {2} - 2y - 3 = 0 \\ {y}^{2} - 3y + y - 3 = 0 \\ (y + 1)(y - 3) = 0 \\ y = - 1 \\ y = 3$

hope it is helpful

Answer 2

Answer:

Here's your answer

Step-by-step explanation:

$2y^{2} + 2y - 3 = 0$

discriminint

$D = b^{2} - 4ac\\D = 2^{2} - 4(2)(-3)\\D = 4 + 24\\D = 28$

by quadratic formula

$y = \frac{-b +- \sqrt{D} }{2a}\\y = \frac{-2 +- \sqrt{28} }{2*2}\\y = \frac{-2 +- 2\sqrt{7} }{4} \\So,\\y = \frac{-2 + 2\sqrt{7} }{4} \\OR\\y = \frac{-2 - 2\sqrt{7} }{4}$

hope u understand