Question

solve the quadratic equation
$(2x + 3) ^{2} = 16$
by factorization method.​

Answer 1

Answer:

$\sf\fbox\red{Answer:-}$

$(2x + 3) ^ 2 = 16//</p><p>4x ^ 2 + 12x + 9 = 16//</p><p>4x ^ 2 + 12x - 7 = 0//</p><p>4x ^ 2 + 14x - 2x - 7 = 0//</p><p>2x * (2x + 7) - 1(2x + 7) = 0//</p><p>(2x - 1)(2x + 7) = 0 x = 1/2 , -7/2$

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(2x + 3) ^ 2 = 16

4x ^ 2 + 12x + 9 = 16

4x ^ 2 + 12x - 7 = 0

4x ^ 2 + 14x - 2x - 7 = 0

2x * (2x + 7) - 1(2x + 7) = 0

(2x - 1)(2x + 7) = 0 x = 1/2 , -7/2

Answer 2

(2x+3)² = 4²

(2x+3)-4² = 0

(2x+3+4) (2x+3-4) = 0

(2x+7) (2x-1) = 0

x = -7/2 or x = 1/2

The above answer is provided by a moderator so it's 100% correct.