Question

solve the quadratic equation
$3x^{2} + 2ax - {a}^{2} = 0$

Answer 1

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$3x^{2} + 2ax - {a}^{2} = 0 \\ \\ 3x^{2} + 3ax - ax - {a}^{2} = 0 \\ \\ 3x(x + a) - a(x + a) = 0 \\ \\ (x + a)(3x - a) = 0 \\ \\(x + a) = 0 \: \: \: and \: (3x - a) = 0 \\ \\ x = - a \: \: and \: \: \frac{a}{3}$

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