Question

solve the quadratic equation
$\sqrt{2{x}^{2 } } + 7x + 5 \sqrt{2} = 0$
dy factorisation method​

Answer 1

Answer:

5/√2,√2

Step-by-step explanation:

use the formula

-b+/-√b^2-4ac/2a

Answer 2

$Given,$

√2x² + 7x + 5√2 = 0

or 2x² + 2x + 5x + 5√2 = 0

or x√2(x +√2) + 5(x+√2) = 0

or (x√2 + 5) (x + √2) = 0

$x = - \frac{5}{ \sqrt{2} } \: , - \sqrt{2}$

These are the required roots.

Hope it helps! ♡