Question

Solve the quadratic equation using appropriate method.
Answer With Solution.

1.) x²- 81= 0
2.) x²+ 5x+ 6= 0
3.) x²+ 3x- 4= 0​

Answer 1

Enjoy your answer. Hope you will understand

Answer 2

Solution :-

1)

→ x² - 81 = 0

→ x² - 9² = 0

using a² - b² = (a - b)(a + b) ,

→ (x - 9)(x + 9) = 0

putting both equal to zero now we get,

→ x - 9 = 0

→ x = 9

and,

→ x + 9 = 0

→ x = (-9)

therefore, x = 9 and (-9) .

2)

→ x² + 5x + 6 = 0

splitting the middle term,

→ x² + 2x + 3x + 6 = 0

→ x(x + 2) + 3(x + 2) = 0

→ (x + 2)(x + 3) = 0

putting both equal to zero now we get,

→ x + 2 = 0

→ x = (-2)

and,

→ x + 3 = 0

→ x = (-3)

therefore, x = (-2) and (-3) .

3)

→ x² + 3x - 4 = 0

splitting the middle term,

→ x² + 4x - x - 4 = 0

→ x(x + 4) - 1(x + 4) = 0

→ (x + 4)(x - 1) = 0

putting both equal to zero now we get,

→ x + 4 = 0

→ x = (-4)

and,

→ x - 1 = 0

→ x = 1

therefore, x = (-4) and 1 .

Learn more :-

solution of x minus Y is equal to 1 and 2 X + Y is equal to 8 by cross multiplication method

https://brainly.in/question/18828734