Question

Solve the quadratic equation using formula:
3a²x2 + 8abx + 4b2 = 0, a≠0.​

Answer 1

Answer:

x = - 2b/3a  or  - 2b/a

Step-by-step explanation:

(i) 3a2x2 + 8abx + 4b2 = 0

⇒ 3a2x2 + 6abx + 2abx + 4b2 = 0

⇒ 3ax(ax + 2b) + 2b(ax + 2b) = 0

⇒ (3ax + 2b) (ax + 2b) = 0

⇒ x = - 2b/3a  or  - 2b/a

∴The answer is x = - 2b/3a  or  - 2b/a

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Answer 2

Step-by-step explanation:

= 3a2x2 + (6 + 2) abx + 4b2 = 0

= 3a2x2 + 6abx + 2abx + 4b2 = 0

= 3ax (ax + 2b) + 2b (ax + 2b) = 0

= (3ax + 2b) + (ax + 2b) = 0

if. 3ax + 2b = 0 , ax + 2b = 0

3ax = -2b ax = -2b

x = -2b x = -2b

3a a

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